Timeline for How to calculate the back radiation from greenhouse gases?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Sep 24, 2021 at 10:32 | answer | added | Pat | timeline score: 1 | |
| Sep 9, 2021 at 13:44 | comment | added | AtmosphericPrisonEscape | I presume you'd need the full solution for the steady-state of the radiation field, i.e. solve the two-stream radiative transport equations for that. Once you have the full solution, you can substract the diffusive radiation from your first atmospheric layer to get the backradiation. I can point you to a source for the full solution for irradiated exoplanets, i'm not familiar with the terrestrial literature. | |
| Sep 5, 2021 at 14:50 | comment | added | import_hill | David Hammen kindly ellaborate | |
| Sep 5, 2021 at 14:42 | comment | added | import_hill | How would we use that to calculate for the back radiation? I've never done this before. | |
| Sep 5, 2021 at 14:40 | comment | added | David Hammen | The diagram clearly shows that only 235 watts per square meter of the incoming solar energy is absorbed by the Earth. The rest (107 watts per square meter) is reflected by clouds, the Earth's surface, etc. | |
| Sep 5, 2021 at 14:38 | comment | added | import_hill | So are you saying the diagram is wrong or something? Also, what does the incoming solar energy absorbed tell us about the back radiation? Thanks | |
| Sep 5, 2021 at 14:34 | comment | added | David Hammen | Incoming solar energy absorbed by the planet is 235 watts per square meter per the diagram in the question (and that diagram is dated; it was produced in 1997). That value (235) is less that 324. | |
| S Sep 5, 2021 at 12:37 | review | First questions | |||
| Sep 5, 2021 at 12:38 | |||||
| S Sep 5, 2021 at 12:37 | history | asked | import_hill | CC BY-SA 4.0 |