# How to perform precipitation data analysis? [closed]

I want to make precipitation data analysis for the Latvian territory. I only have meteorological stations and reanalysis data. My data from meteorological stations are in the format:

year  month  day    time      station1 station2 station3
2013    1     1    03.00        0                 0.1
2013    1     1    06.00        0.1               0.2
2013    1     1    15.00        0       0.1         0
2013    1     1    18.00        0.2     0         0.3
2013    1     2     03.00        0                 0.4
...


I also have a file with coordinates for meteorological stations. And data from reanalysis is in format

> head(data)
longitude latitude   time value
1     -27.0      -27 990555     0
2     -25.5      -27 990555     0
3     -24.0      -27 990555     0
4     -22.5      -27 990555     0
5     -21.0      -27 990555     0
6     -19.5      -27 990555     0


Edited: My main questions are: 1) What can tell me if these data are similar, should I look their summary and compare, or it is better to use some tests. Could you advice methods how to compare different data. 2) If there are missing values, should I just get them out and then analyse data?
3) Maybe someone can advice some tutorial with R code? Can someone tell me how to decode time values from format like 990555 (I need formula or function for R)?

## closed as unclear what you're asking by Semidiurnal Simon, Peter Jansson, blunders, BHF, arkaiaMay 28 '14 at 13:17

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

• Unclear what you're asking - we need to know what you actually want to do with this data; what you want to find out. voting to close, but perhaps you could add some more detail and see if it gets reopened? – Semidiurnal Simon May 27 '14 at 12:50
• Hi Student, thanks for the revisions and clarification. Now that I can see what you're asking, I think that you might be better off asking the first half on statistics.SE, and for the second half doing some searching (I think Stackoverflow would want to see some more research before helping) – Semidiurnal Simon May 29 '14 at 8:52

• @Student To stay in R you can use this snippet as.POSIXct(990555*3600, origin="1900-01-01 00:00:00"). The standard to represent time in R and in most modern languages is POSIX and in this standard time is represented in seconds not hours, hence the multiplication by 3600. – plannapus Jun 16 '14 at 8:32