9
$\begingroup$

So on land, I believe that one factor in their formation is due to inhomogeneities in surface heating between land and ocean (and also inhomogeneities in surface heating due to terrain effects like the Rocky Mountains).

But what about in the ocean, where we don't see such inhomogeneities? How is the formation and movement of Rossby Waves in ocean different from that of land?

$\endgroup$
14
$\begingroup$

First, inhomogeneities in the ocean are in fact quite common. There are density gradients in both horizontal and vertical directions and those gradients result in the baroclinic circulation of the ocean. The density gradients in the ocean are caused by salinity and temperature differences.

Rossby waves are common in the ocean. They propagate along lines of latitude with the waves traveling along the Equator being the most obvious example and the most thoroughly studied. As in the case of atmospheric Rossby waves, their formation and propagation is related to the conservation of (potential) vorticity (rotational movement, angular momentum). A parcel of water has two sources of vorticity: its own spin and the planetary spin. When a parcel of water moves across a latitudinal line, its planetary spin (planetary vorticity) changes (as the Coriolis effect is latitudinally dependent) and, in order to conserve vorticity, it changes its own spin (relative vorticity). The water parcel tends to swing back and forth around the original latitude resulting in a wave-like motion. A Rossby wave is characterized by a westward phase velocity (that of the wave crests).

$\endgroup$
  • $\begingroup$ Isn't it conservation of Potential Vorticity? $\endgroup$ – Isopycnal Oscillation Apr 24 '14 at 5:03
  • 2
    $\begingroup$ I was trying to keep it simple, but I have added your suggestion. $\endgroup$ – arkaia Apr 29 '14 at 17:16
12
$\begingroup$

To add to the excellent answer by aretxabaleta:

This is what happens for eastward flow over a step change in depth. Note that the wavy pattern is seen from above, and it veers right due to the step and the conservation of potential vorticity (and the fact it is in the Northern Hemisphere). Similar to a particle displaced from its equilibrium in a buoyancy field, the particle veers right towards the latitude that is its new equilibrium point. However, due to its momentum it overshoots the equilibrium latitude. When it returns, the same happens and so on forever (in linear terms), thus giving origin to the wave.

enter image description here

(from kundu)

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.