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How much would 1 m3 of an ideal mineral SOIL that has been completely dried (all pore space is empty) weigh in Mg on Earth? Answer = ______ Mg

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  • $\begingroup$ I am confused if I just calculate m or Mg or if it more complicated due to the fact that there is no pore space $\endgroup$ – zan867 Feb 11 '19 at 20:07
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    $\begingroup$ I don't know how you would calculate this because the pores, now empty of all moisture, vary based on the size and shape, and development, of the mineral soil. $\endgroup$ – user824 Feb 11 '19 at 22:53
  • $\begingroup$ I think this is just based on a generalized particle density $\endgroup$ – zan867 Feb 11 '19 at 23:30
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    $\begingroup$ Just to be clear I am not a soil scientist but how do you generalize the particle density. I am thinking that the mineral soil component of various types of soils would have vastly different pore sizes. Clay based soil would have a much higher density than a colluvium based soil. Again I am likely missing something from the question. $\endgroup$ – user824 Feb 12 '19 at 0:00
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    $\begingroup$ Depends on composition. sandy soil composed of mainly quartz will have a near 2.65 g/cm^3 but clayey soils will be considerably more dense. $\endgroup$ – Gary Kindel Feb 12 '19 at 12:43

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