# Is there a way to approximate the density of air during rain?

Given a rate of precipitation (in mm^3/hour), and average droplet diameter, is is it possible to calculate (or even ballpark) the density of the air+rain droplets at time of rainfall?

What I mean is, if I were to take a random metric cube of rain+air during rainfall, how much would it weigh?

• The unit you suggest is not correct for rain rate, you would need to divide it by a surface area. That would give you for example mm/hour which equals L/m^2/hour. – Basileios May 10 at 20:22

Air without rain has a mass of about $$\ce{1200 g/m^3}$$ at 20°C.
Here's a link to a post elsewhere on this same question. In that discussion, they assume a rainfall rate of 1 inch (2.54cm) per hour, and estimate a raindrop's terminal velocity (from observation) at about 9 m/s. They divide that rate by that velocity (converting units), and come up with about $$\ce{3/4 cm^3}$$ of water per $$\ce{m^3}$$ of rain.