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I am working on the global CO2 emission using a model dataset. The model provides the CO2 emission in mol m-2 s-1. How to convert mol m-2 s-1 CO2 emission to Megaton day-1 (Mt per day)?

Regards

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  • $\begingroup$ You don't have enough information. You have a flux rate, so without a defined area, you can't convert to daily emissions. You can easily convert moles to Mt, and seconds to days, but you still need an area defined. $\endgroup$
    – f.thorpe
    May 4 at 14:22
  • $\begingroup$ Thank you sir, your answer solved the problem. There was a global dataset, and the area was 510.1 million km². $\endgroup$ May 4 at 14:52
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Do the calculation for 1 mol of CO$_2$

1 mol of CO$_2$ weighs 49 grammes = 0.0049 kg

86400 seconds in a day, so 864000 * 0.0049 = 423.36 kg/day/m$^2$

The surface area of the globe is 5.1 x 10$^{14}$ m$^2$ - so 423.6 * 5.1 x 10$^{14}$ = 2.16 x 10$^{17}$ kg/day

Convert from kg to Megatons, 10$^9$ kg in a Megaton - so we get 1 mol CO$_2$/m$^2$/second = 2.16 x 10$^8$ Megatons/day

This assumes, as farrenthorpe commented, that the molar emission rate represents a rate evenly distributed over the globe - if, for instance it only represented terrestrial emissions, or emissions in a particular region the calculation would need to take that into account.

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  • $\begingroup$ Thank you sir for explaining in detail. It helped out. $\endgroup$ May 4 at 14:55
  • $\begingroup$ Farhan - happy to help out. I just edited my answer as I had made an error in units that changed the answer. I missed conversion from square metres to square kilometres! $\endgroup$
    – Andy M
    May 4 at 15:57

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