# What is the difference between roughness length and zero plane displacement?

Both roughness length $z_0$ and zero plane displacement $d$ seemed to be defined as the height above the ground at which wind speed theoretically becomes zero. But wind speed is also supposed to go to zero at $d+z_0$. What is the difference between the two, and how should they actually be defined?

• It would be useful if you included a reference for the equivalent definition of $z_0$ and $d$. – milancurcic Apr 8 '15 at 17:57

First some definitions:

$z_0$: Roughness length is defined as the height at which the mean velocity is zero due to substrate roughness. Real walls/ground are not smooth and often have varying degrees of roughness, this parameter (which is determined empirically) accounts for that effect.

$d$: Zero Plane displacement is defined as the height at which the mean velocity is zero due to large obstacles such as buildings/canopy.

The two parameters are not the same because they describe the effects of two fundamentally different processes. $d$ can be anywhere from $6$ to $20$ times larger than $z_0$.

The basis for most turbulence modeling is the eddy viscosity model:

$$-\overline{u'w'} = \nu_t \frac{\partial U}{\partial z}$$

where $\nu_t$ is the eddy viscosity. Employing some scaling arguments with basis on the Prandtl mixing length model and integrating one arrives at the logarithmic law of the wall:

$${U} = \frac{u^*}{\kappa} \ln\, \frac{z}{z_0}$$

$${U} = \frac{u^*}{\kappa} \ln\, \frac{z-d}{z_0}$$ which is the law of the wall with $d = 0$ because it applies to flat plates. It is easy to see then, that by subtracting $d$ from $z$ the effect is to reduce $U$ at that height, which makes sense because large obstacles remove energy from the mean flow and slow it down.
Note that if there are no large obstacles then $d \approx 0$, but $z_0$ is still larger than zero.