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Specifically, if the daily production of ozone and cfc were at most 400 million and 3k tons, respectively, would each mol of cfc be able to destroy tens of thousands of mols of ozone? All the sources I can find show cfc being much less potent than that.

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closed as unclear what you're asking by hichris123 Aug 27 '16 at 15:26

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

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    $\begingroup$ please share the references you are discussing $\endgroup$ – farrenthorpe Aug 25 '16 at 2:40
  • $\begingroup$ I don't see what the daily production has to do with the question about the number of mols. $\endgroup$ – Jan Doggen Aug 26 '16 at 7:34
  • $\begingroup$ The question raised in the title, What is the science behind CFCs depleting the ozone layer, is readily answered by asking that question of the internet oracle (i.e., google). Even the lesser oracles (e.g., yahoo and bing) can answer this question. $\endgroup$ – David Hammen Aug 28 '16 at 18:03
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I guess nobody has given DJ Sims the simple answer he/she wants because such a generalized question is indeterminate. The chlorine is relatively stable, so 'how many ozone mols are destroyed' depends upon the availability of relatively short-lived ozone. In a dry atmosphere this is very much a function of temperature. At -50 deg C ozone's half life is about 3 months, but at 0 deg C it is only about 5 days. It also depends upon humidity, pH and a swag of associated high-atmospheric reactions. The ozone availability is also a function of ozone's regeneration rate.

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  • $\begingroup$ @DJSims That's a creative interpretation. Gordon says that you cannot give a simple figure because it depends on too many factors. You conclude that thus there is no evidence. How about you doing some homework first and answering the comments under your question? That would help people to know what to answer to without having to write an entire textbook . $\endgroup$ – Jan Doggen Aug 26 '16 at 7:42

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